Respuesta :
[tex] {( \frac{ {3}^{4} \times {3}^{8} }{ {3}^{6} } )}^{ - 3} = {( \frac{ {3}^{4 + 8} }{ {3}^{6} } )}^{ - 3} = {( \frac{ {3}^{12} }{ {3}^{6} } )}^{ - 3} = {( {3}^{12 - 6} )}^{ - 3} = { ({3}^{6}) }^{ - 3} = {3}^{ - 3 \times 6} = {3}^{ - 18} [/tex]