[tex]|\frac{2x-1}{x+3}|\leq1\\\\-1\leq\frac{2x-1}{x+3}\qquad\qquad\ \frac{2x-1}{x+3}\leq 1\\\\-x-3\leq2x-1\qquad2x-1\leq x+3\\\\-\frac{2}{3}\leq x\qquad\qquad\qquad x\leq4\\\\-\frac{2}{3}\leq x\leq4\\\\\\x\in\mathbb Z / -\frac{2}{3}\leq x\leq4\\\\x:0;1;2;3;4\\\\4+3+2+1+0=10[/tex]