resolver esta ecuacion:
1) logx=log5 +1
2) logx=log3 + 2log2
[tex]\\\log x=\log5 +1 \\ x>0\\ \log x-\log5=1\\ \log\frac{x}{5}=1\\ 10=\frac{x}{5}\\ x=50\\[/tex]
[tex]\\\log x=\log3 + 2\log2\\ x>0\\ \log x=\log 3+\log 4\\ \log x=\log 12\\ x=12[/tex]
