Pierrotask
contestada

Me ayudarian con esto ^^

Suma algebraica de numeros complejos

A) (3/2 + 1/5i) + (-1/3 + 4i) - (1/2 - 1/5i)=

B) (1/4i) - (-5i) - (3i)=

C) (5i) + (-3+4/5i) - (-3/5i) - (-3-4/5i)=

D) (-1/3i) + (1/3 + 3i) + (-1/3 - 3i) + (-5i)=

Respuesta :

Carlosdario1993ask

A) (3/2 + 1/5i) + (-1/3 + 4i) - (1/2 - 1/5i)=



(15i+2)/10i + (-1+12i)/3- (5i-2)/10i=

 

(3(15i+2)+10i (-1+12i)-2(5i-2))/30i=

 

(15i+6-10i+120i2-10i+4)/30i=

 

(120i2-5i+4)/30

 

B) (1/4i) - (-5i) - (3i)=


1/4i+5i-3i=


1/4i+2i=


(1+8i2)/4i



 

 

 

 

 

 

 

 

 

 

 

 

 

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